5x^2+10x-18=-8

Solution for 5x^2+10x-18=-8 equation:

5x^2+10x-18=-8

We move all terms to the left:

5x^2+10x-18-(-8)=0

We add all the numbers together, and all the variables

5x^2+10x-10=0

a = 5; b = 10; c = -10;
Δ = b2-4ac
Δ = 102-4·5·(-10)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{3}}{2*5}=\frac{-10-10\sqrt{3}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{3}}{2*5}=\frac{-10+10\sqrt{3}}{10}
$